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The lea esi,[edi+0x18] at address 00401027 seems innocent, but what happens if EDI contains a very high value that s close to 0xffffffff In such a case, the addition would overflow and the result would be a low positive number, possibly lower than the length of the buffer itself! Suppose, for example, that you feed the function with 0xfffffff8 as the buffer length 0xfffffff8 + 0x18 = 0x100000010, but that number is larger than 32 bits The processor is truncating the result, and you end up with 0x00000010 Keeping in mind that the buffer length copied by the function is the original supplied length (before the header length was added to it), you can now see how this function would definitely crash.

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The Monte Carlo simulation was carried out with 100, 1000, and 10,000 samples. Table 17.3 gives the results for one set of runs. Figures 17.4, 17.5 and 17.6 show the corresponding plots of the ordered results. In each plot the dashed line is the result of the Monte Carlo simulation and the solid line is the exact cumulative distribution for the margin of safety. The table and plots show that, while the results from a simulation using 100 points give a general picture of the true answer, 1000 points or more are necessary to obtain accurate results. An additional bene t of the plots is that, generally, the smoother the curves the more accurate the results.

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Or do you arrive with just enough time to rig and launch immediately (Some people will require more or less time on the race course to get familiar with the conditions.) Consider which approach will leave you the most mentally t and best prepared. You may nd that a different approach will work on different days. For example, if you are racing in the afternoon, having a light pasta lunch and then going to the boat park may work best, but if you are morning racing you may choose to rig and then have breakfast. Some people nd that their mental and physical states affect their eating patterns. Some may nd that eating will help settle the nerves (and the stomach) and prevent stomach cramps. Others will not feel like eating, so they need to eat breakfast earlier than normal as the stress may slow their digestion. However you react, try not to worry about it; just look back in your racing log to see what works best for you (eating normally, eating early, just taking energy drinks).

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The malloc call will allocate a buffer of 0x10 bytes long, but the function will try to copy 0xfffffff8 bytes to the newly allocated buffer, thus crashing the program The solution to this problem is to take a limited-sized input and make sure that the target variable can contain the largest possible result For example, assuming that 16 bits are enough to represent the user buffer length; simply changing the preceding program to use an unsigned short for the user buffer length would solve the problem Here is what the corrected version of this function looks like:.

allocate_object: 00401024 push 00401025 movzx 0040102a push 0040102b lea 0040102e push 0040102f call 00401034 pop 00401035 xor 00401037 cmp 00401039 jnz 0040103b xor 0040103d jmp 0040103f mov 00401042 mov 00401045 mov esi esi,word ptr [esp+0xc] edi edi,[esi+0x18] edi 7!malloc (004010dc) ecx ecx,ecx eax,ecx 7!allocate_object+0x1b (0040103f) eax,eax 7!allocate_object+0x43 (00401067) [eax+0x4],ecx [eax+0x8],ecx [eax+0xc],ecx

Figure 17.4 Ordered sequence of results for 100 simulations of vertical cut problem (dashed line). The solid line is the exact answer.

7

00401048 0040104b 0040104e 00401050 00401054 00401056 00401058 0040105b 0040105e 00401060 00401062 00401065 00401067 00401068 00401069 mov mov mov mov mov mov shr lea rep mov and rep pop pop ret [eax+0x10],ecx [eax+0x14],ecx ecx,esi esi,[esp+0xc] edx,ecx [eax],edi ecx,0x2 edi,[eax+0x18] movsd ecx,edx ecx,0x3 movsb edi esi

Figure 17.5 Ordered sequence of results for 1000 simulations of vertical cut problem (dashed line). The solid line is the exact answer.

This function is effectively identical to the original version presented earlier, except for movzx esi,word ptr [esp+0xc] at 00401025. The idea is that instead of directly loading the buffer length from the stack and adding 0x18 to it, we now treat it as an unsigned short, which eliminates the possibly of causing an overflow because the arithmetic is performed using 32-bit registers. The use of the MOVZX instruction is crucial here and is discussed in the next section.

1. Over tired 2. Not enjoying racing/training 3. Don t care about result/distracters 4. Feeling under pressure to perform 5. Nervous (may have related tummy issues)

Figure 17.6 Ordered sequence of results for 10,000 simulations of vertical cut problem (dashed line). The solid line is the exact answer.

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